2018 Glasgow Trophy – Doubles
2018 tennis event results
Doubles | |||
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2018 Glasgow Trophy | |||
Final | |||
Champions |
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Runners-up |
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Score | 6–1, 7–5 | ||
Events | |||
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Main article:
2018 Glasgow Trophy
This was the first edition of the tournament.
Gerard Granollers and Guillermo Olaso won the title after defeating Scott Clayton and Jonny O'Mara 6–1, 7–5 in the final.
Seeds
-
Scott Clayton /
Jonny O'Mara (final)
-
Roberto Ortega Olmedo /
Mario Vilella Martínez (first round)
-
Alessandro Bega /
Lucas Miedler (quarterfinals)
-
Harri Heliövaara /
Evgeny Karlovskiy (semifinals)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 |
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6 7 | 6 | [10] | |||||||||||||||||||||||
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7 9 | 2 | [5] | 1 |
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6 | 6 | ||||||||||||||||||||
PR |
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6 5 | 6 | [6] | PR |
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4 | 2 | |||||||||||||||||||
PR |
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7 7 | 2 | [10] | 1 |
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6 | 6 | |||||||||||||||||||
3 |
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3 | 7 9 | [10] |
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3 | 2 | ||||||||||||||||||||
WC |
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6 | 6 7 | [6] | 3 |
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6 5 | 6 | [5] | ||||||||||||||||||
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1 | 1 |
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7 7 | 1 | [10] | |||||||||||||||||||||
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6 | 6 | 1 |
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1 | 5 | |||||||||||||||||||||
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3 | 6 | [10] |
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6 | 7 | |||||||||||||||||||||
Alt |
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6 | 3 | [4] |
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3 | 6 2 | ||||||||||||||||||||
WC |
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2 | 2 | 4 |
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6 | 7 7 | ||||||||||||||||||||
4 |
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6 | 6 | 4 |
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3 | 4 | ||||||||||||||||||||
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4 | 6 | [5] |
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6 | 6 | |||||||||||||||||||||
WC |
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6 | 2 | [10] | WC |
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5 | 4 | |||||||||||||||||||
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7 | 6 |
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7 | 6 | ||||||||||||||||||||||
2 |
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5 | 3 |